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0=-0.8x^2+3.2x+6
We move all terms to the left:
0-(-0.8x^2+3.2x+6)=0
We add all the numbers together, and all the variables
-(-0.8x^2+3.2x+6)=0
We get rid of parentheses
0.8x^2-3.2x-6=0
a = 0.8; b = -3.2; c = -6;
Δ = b2-4ac
Δ = -3.22-4·0.8·(-6)
Δ = 29.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.2)-\sqrt{29.44}}{2*0.8}=\frac{3.2-\sqrt{29.44}}{1.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.2)+\sqrt{29.44}}{2*0.8}=\frac{3.2+\sqrt{29.44}}{1.6} $
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